Finding Force to Pull 150lb Sled on Horizontal Surface

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In summary, to pull a 150-pound sled along a horizontal surface with a coefficient of friction of 0.10 and a rope making a 30-degree angle with the horizontal, you would need a force of approximately 17.32 pounds.
  • #1
science_again
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What force is required to pull a 150-pound sled along a horizontal surface? The coefficient of friction is 0.10 and the sled is pulled by a rope which makes an angle of 30 degrees with the horizontal?
 
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  • #2
Hello science_again

What have you done to solve this problem?
Have you drawn a free-body diagram for the sled.
 
  • #3
This is where I am at.

F cos 30 - 0.10(friction) = 0
F cos 30 = 0.10 x normal force (Fn) [1]
Fn + F sin 30 - weight of sled = 0 [2]

Therefore substitute, put [2] in [1] you get 0.866F = 0.1(weight of sled - 0.5F)

should the weight of sled convert to kg?
 
  • #4
science_again said:
This is where I am at.
should the weight of sled convert to kg?
You don't need to.
 
Last edited:
  • #5
F cos 30 - 0.10(friction) = 0
F cos 30 = 0.10 x normal force (Fn) [1]
Fn + F sin 30 - weight of sled = 0 [2]

That looks correct.
Try and work out F using symbols and then substitute the numbers at the end of the problem.
This makes it easier to avoid errors.

should the weight of sled convert to kg?
Normally you would use the same units that the question uses, so pounds would be ok.
 
  • #6
Thanks
 

1. How do I calculate the force needed to pull a 150lb sled on a horizontal surface?

The force needed to pull a 150lb sled on a horizontal surface can be calculated using the formula F = ma, where F is the force (in newtons), m is the mass of the sled (in kilograms), and a is the acceleration (in meters per second squared). In this case, the mass of the sled is 150lbs, which is equivalent to 68.04 kilograms. The acceleration can be determined by dividing the distance the sled needs to be pulled by the time it takes to pull it. For example, if the sled needs to be pulled 10 meters in 5 seconds, the acceleration would be 2 meters per second squared. Plug these values into the formula and you will get the force needed to pull the sled.

2. Is there a specific type of force that is best for pulling a 150lb sled on a horizontal surface?

The type of force that is best for pulling a 150lb sled on a horizontal surface will depend on the surface itself. If the surface is smooth and flat, then a constant force would be ideal. However, if the surface is rough or uneven, a variable force may be needed to navigate through any obstacles.

3. How does the incline or decline of the surface affect the force needed to pull a 150lb sled?

The incline or decline of the surface can have a significant impact on the force needed to pull a 150lb sled. On an incline, the force needed to pull the sled will increase as the angle of incline increases. On a decline, the force needed to pull the sled will decrease as the angle of decline increases. This is due to the change in gravity and the distribution of weight on the sled.

4. Are there any external factors that can affect the force needed to pull a 150lb sled on a horizontal surface?

Yes, there are several external factors that can affect the force needed to pull a 150lb sled on a horizontal surface. These include friction, wind resistance, and the weight of the sled itself. Friction, in particular, can greatly impact the force needed to pull the sled, as it can create resistance and make it more difficult to move the sled.

5. How can I determine the maximum force I am capable of exerting to pull a 150lb sled on a horizontal surface?

The maximum force you are capable of exerting to pull a 150lb sled on a horizontal surface will depend on your own physical capabilities. To determine this, you can perform a strength test, such as a one-rep max test, to determine the maximum amount of force you can exert in a single pull. It is important to remember to always use proper form and technique when exerting force to avoid injury.

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