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I know that the the vertical component is 476 N, the other one's I have no clue of how to do. I made the sum of the forces in the x direction zero. So I know that the force of static friction will equall the normal force exerted by the wall. I also made the sum of the torques to equal zero. So, FnLn = FwLw. I get my answer to be 137.41 N, but this is not right. Ln represents the lever arm's lengh. I used trig functions to get Lw=cos60 (0.75), and Ln=sin60 (1.5)

This is the drawing they provide the distance (hypotenuse) from the Fn to the ground as 1.5. This number is broken into 1.1 m for her feet to the waist and 0.4 m from waist to shoulders. The head isn't included since there is no force for it.