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I have a problem that I am having difficulties with. I'm told to find the general integral.

So here is the problem:

[itex]\int_{\frac {\pi} {2}}^{\frac {-\pi} {2}} \frac {sinx} {1 - sin^2 x} dx[/itex]

Here is my partial solution:

[itex]\int_{\frac {\pi} {2}}^{\frac {-\pi} {2}} \frac {sinx} {cos^2 x} dx[/itex]

[itex]\int_{\frac {\pi} {2}}^{\frac {-\pi} {2}} \frac {1} {cosx} * \frac {sinx} {cosx} dx[/itex]

[itex]\int_{\frac {\pi} {2}}^{\frac {-\pi} {2}} secxtanx dx[/itex]

[itex]= [tanx][/itex]

But here is where I am stuck, because when you evaluate [itex]tanx[/itex] from [itex]\frac {\pi} {2}[/itex] to [itex]\frac {-\pi} {2}[/itex] you get an error because no value exists for [itex]tan \frac {\pi} {2}[/itex]

Any help would be greatly appreciated.

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# Homework Help: Finding the general integral

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