1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Finding the Identity

  1. Jul 15, 2011 #1
    I'm having trouble finding the identity of an operation. Could someone check my work?

    I'm trying to find the identity of x*y = x + 2y - xy
    In order to find the identity, I need to solve x*e = x for e

    [tex]
    \begin{align*}
    x*e &= x\\
    x + 2e - xe &= x\\
    2e - xe &= 0\\
    e(2-x) &= 0\\
    \end{align*}
    [/tex]
    In order for e(2-x) = 0 to be true e = 0

    Then I need to check if x*0 = x, which is true.
    And then check if 0*x = x, which is NOT true, since 0*x = 2x.

    So there is no identity and no inverse for the operation x*y = x + 2y - xy
     
  2. jcsd
  3. Jul 15, 2011 #2

    micromass

    User Avatar
    Staff Emeritus
    Science Advisor
    Education Advisor
    2016 Award

    Looks ok, IKonquer!! :smile:
     
  4. Jul 15, 2011 #3
    Wow. Thanks for the quick response micromass! :smile:

    What about this one?

    x*y = |x+y|

    To find the identity, x*e = x

    x*e = |x + e| = x

    The absolute value can be broken up into two cases:

    1) x + e = x
    e = 0

    In order to be an identity x*e =x and e*x = x
    x*0 = |x+0| = x
    0*x = |0+x| = x

    So 0 is an identity element.

    ---------------------------

    2)x + e = -x
    e = -2x

    In order to be an identity x*e =x and e*x = x
    x*(-2x) = |x+(-2x)| = x
    (-2x)*x = |(-2x)+x| = x

    So -2x is an identity element.

    ---------------------

    So it seems like both 0 and -2x are both identities over the operation. Is this possible? And if two identities can occur, then every number under this operation has two identities.
     
  5. Jul 15, 2011 #4

    micromass

    User Avatar
    Staff Emeritus
    Science Advisor
    Education Advisor
    2016 Award

    First of all, -2x can never be an identity. Your identity cannot be dependent on x!!
    Second, you made a mistake here:

    |x+0| is not x, is it? :frown:
     
  6. Jul 15, 2011 #5
    I see, |x+0| = |x| = +x or -x. As a result there should be no identity.

    So is it usually the case that most operations don't have an identity?
     
  7. Jul 15, 2011 #6

    micromass

    User Avatar
    Staff Emeritus
    Science Advisor
    Education Advisor
    2016 Award

    Uuh, well, it depends with what you mean with "usually" :smile: Let's just say that having an identity provides quite a lot of structure on the set, so in that regard, it's quite rare for an operation to have an identity. However, you can always adjoin an identity to every set. For example

    [tex]\{1,2,3,4,5,...\}[/tex]

    has no identity for the normal addition. But if we adjoin 0 to the set, then we do have an identity on the set.

    Let's just say that the most operations that you'll ever meet will have an identity :smile:
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook