# Finding the Improper integrals

1. Oct 12, 2004

### ACLerok

I am trying to find the integral of [ln(x)] / [sqrt(x)]. i tried doing it by u substitution but that failed. what is the easiest way to do it? Also, I evaulated the integral from 1 to infinity of [ln(x)]/x by treating as an improper integral.
The way i did it was by setting up lim(as t->infinity) integral(1 to t) [ln(x)]/x. This correct, i got -1 so that means it diverges right? Or is my answer wrong?

2. Oct 12, 2004

### Pyrrhus

I think you got to use integration by parts.

3. Oct 13, 2004

### ACLerok

k, i will try integrating by parts but am i right about the second integral?

4. Oct 13, 2004

### ACLerok

can anyone else help me out please?

5. Oct 13, 2004

### TenaliRaman

lnx = 2t
x = e^2t
taking sqrt on both sides,
sqrt(x) = e^t
1/2*sqrt(x) dx = e^t dt

-- AI

6. Oct 13, 2004

### ACLerok

this may be a dumb question but whre is that from?

7. Oct 14, 2004

### TenaliRaman

oh i missed the word substitute ...
:tongue2:
-- AI