1. The problem statement, all variables and given/known data find the inflection points of x^2-4√x 2. Relevant equations 3. The attempt at a solution Okay, I started with finding the derivatives; f'(x)=2x-2/√x f''(x)=2+1/√x^3 and made the second derivative =0 (2+1/√x^3=0)(√x^3) 2√x^3+1=0 (√x^3=-1/2)^2 x^3=1/4 x=cube root(1/4) x=0.63 But when I enter '0.63' into the second derivative i get '4' (2+1/(√0.63^3)=4) Should i not get 0? Does this mean there are no inflection points?