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Calculus and Beyond Homework Help
Finding the inverse matrix responsible for base change in the Z3 Group
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[QUOTE="Dixanadu, post: 4538448, member: 451060"] [h2]Homework Statement [/h2] Hey guys, So I have the following permutations, which are a subgroup of S3: [itex]σ_{1}=(1)(2)(3), σ_{5}=(1,2,3), σ_{6}=(1,3,2)[/itex] This is isomorphic to Z3, which can be written as [itex]{1,ω,ω^{2}}[/itex] Next, we have the basis for the subgroup of S3: [itex]e_{i}=e_{1},e_{2},e_{3}[/itex] And we also have the basis for the group Z3, which is a linear combination of the basis vectors of S3: [itex]E_{k}=(e_{1}+e_{2}+e_{3}), (e_{1}+ωe_{2}+ω^{2}e_{3}), (e_{1} +ω^{2}e_{2}+ωe_{3})[/itex] I have to find the matrix (and its inverse) which is responsible for the following base change: [itex]E_{k}=S_{jk}e_{j}[/itex][h2]Homework Equations[/h2] Dont think there are any.[h2]The Attempt at a Solution[/h2] So I think I've found the matrix [itex]S[/itex], the problem is that how do I find [itex]S^{-1}[/itex]. I get the following for [itex]S[/itex], even though I'm not sure its right: [PLAIN]http://imageshack.com/a/img401/9545/h213.jpg[/PLAIN] I tried using the regular matrix rules for finding the inverse (transpose of the matrix of cofactors divided by the determinant) but it doesn't seem to work. Can you guys help me out? thanks in advance. [/QUOTE]
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Finding the inverse matrix responsible for base change in the Z3 Group
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