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3(2^(2x+1)+5(2^(-x) )= 31

What I did first was to take the logarithim on both sides of the equation... to solve for x. But that apparently isn't a "logical" way to proceed. Any advice?

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In summary, the conversation revolves around the problem of solving the equation 3(2^(2x+1)+5(2^(-x))= 31 for x and finding the maximum domains. The initial approach of taking logarithms on both sides is deemed illogical, and the suggestion to avoid square roots of negative numbers and not divide by zero is given. However, it is later clarified that the main concern is how to solve for x, and the suggestion to substitute t=2^x and express the equation in terms of t is given. The conversation ends with a reminder to be clear and specific when asking for help.

- #1

- 34

- 0

3(2^(2x+1)+5(2^(-x) )= 31

What I did first was to take the logarithim on both sides of the equation... to solve for x. But that apparently isn't a "logical" way to proceed. Any advice?

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- #2

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- #3

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[3(2^(2x+1))]+[5(2^(-x)] = 31

^ means to the power of ...

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- #5

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- #7

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But then you start asking about solving for x- which has nothing to do with finding a domain. If that really is the problem, dp what Eighty suggested: let t= e

Hint: e

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