Basically, we were told that from (mv^2/r)(cos [tex]\theta[/tex]) = [tex]\mu[/tex][(mv^2)/r) sin [tex]\theta[/tex] + (mg cos [tex]\theta[/tex])] + mg sin[tex]\theta[/tex](adsbygoogle = window.adsbygoogle || []).push({});

you could rearrange for the max speed of a car going in a circular path on a banked road at a [tex]\theta[/tex] angle. From that equation above, I derived v max, but now I need to get v minimal. I really don't even understand the visual concept of the equation above - I drew a free-body diagram but I still don't understand it.

Could someone help me figure out the minimal speed the car has to go without falling off?

Also in the equation, he substituted a variable N for normal force with the equation in the bracket. So it's basically

(mv^2/r)(cos [tex]\theta[/tex]) = [[tex]\mu[/tex]N + (mg cos [tex]\theta[/tex])] + mg sin[tex]\theta[/tex]

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# Homework Help: Finding the minimal speed of

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