x = (2/5)cos(t) + (1/5)sin(t)(adsbygoogle = window.adsbygoogle || []).push({});

by graphing this, I found the period to be 2*pi.

My concern is, when taking an exam I won't have time to bother with graphing or I'll get slammed with a weird graph and panic and get stuck.

I'm pretty sure there is a way to find the period quickly with out graphing? I am running into this problem in my dyamical systems class and my calculus and trig are sooooooooo rusty.

Thanks,

Candio

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# Finding the period of a fxn

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