We have 45.0g of Na3PO4 per liter. We know it is very basic but need the pH. I don't have the answers to all exercises, so if you could check my work, that'd be great. So, we have g, but moles would be more useful. So 45g x (1 mol/163.937) = 2.7 x 10^-1 mol. We know that strong bases completely dissociate in water. Therefore, [Na3PO4]=[OH-]. So, since pOH = - log of all that = 0.569 Therefore: pH = 14 - 0.569 = 13.431 which is indeed pretty basic. Any mistake somewhere? Thank you, Joanna.