We have 45.0g of Na3PO4 per liter. We know it is very basic but need the pH.(adsbygoogle = window.adsbygoogle || []).push({});

I don't have the answers to all exercises, so if you could check my work, that'd be great.

So, we have g, but moles would be more useful.

So 45g x (1 mol/163.937) = 2.7 x 10^-1 mol.

We know that strong bases completely dissociate in water.

Therefore, [Na3PO4]=[OH-].

So, since pOH = - log of all that = 0.569

Therefore: pH = 14 - 0.569 = 13.431 which is indeed pretty basic.

Any mistake somewhere?

Thank you,

Joanna.

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# Homework Help: Finding the pH of TSP

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