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Finding the polar equation

  1. Jan 26, 2014 #1
    1. The problem statement, all variables and given/known data
    Find a polar equation for the curve represented by the Cartesian equation.

    y=1+3x

    2. Relevant equations
    x2+y2=r2
    x=Rcos(θ)
    y=Rsin(θ)

    3. The attempt at a solution
    (1+3x)2+x2=r2
    1+6x+10x2=r2
    1+6rcos(θ)+10r2cos2(Θ)=r2
     
  2. jcsd
  3. Jan 26, 2014 #2

    HallsofIvy

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    Staff Emeritus
    Science Advisor

    Why are you squaring? This will give you a relation between [itex]x^2[/itex] and [itex]y^2[/itex], not x and y, and so not the original equation. Just replace "x" with [itex]r cos(\theta)[/itex] and "y" with [itex]r sin(\theta)[/itex] in the original equations.
     
  4. Jan 26, 2014 #3
    Oh thank makes a lot of sense. Thank you.
     
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