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Introductory Physics Homework Help
Finding the Potential Difference In Parallel Capacitors
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[QUOTE="gneill, post: 5169919, member: 293536"] How did you arrive at a numerical value for the field if you were not given a specific value for q? A dielectric modifies the net electric field strength inside of it, so the field due to a given plate will be different for the two regions. You'd have to account for that. Further, they're looking for the potential across just one of the dielectric regions and you've used the entire distance between the plates, which would yield a potential difference across the the whole capacitor (if the field were in fact uniform). An approach that you might consider is to treat the two dielectric regions as individual capacitors, where a 'virtual plate' occupies the boundary between the dielectrics. Then you can calculate the resulting capacitance of each 'capacitor' separately and apply the relationship Q = CV, where Q is the charge on the capacitor, C is the capacitance, and V the potential difference between the plates. [/QUOTE]
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Introductory Physics Homework Help
Finding the Potential Difference In Parallel Capacitors
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