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Finding the relationship between magnetic momentum and angular momentum
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[QUOTE="Charles Link, post: 5984874, member: 583509"] A follow-in: The result for angular momentum is elementary, so I will post it here: I get ## \vec{L}=\frac{1}{2} MR^2 \omega \hat{z} ##. Using ## Q_{total \, heads} ## and ## Q_{outer \, surface } ## as parameters, (I'm going to post a result here, because that is the only way to discuss the answer I got), I get ## \vec{m}= [Q_{total \, heads} \frac{R^2 \omega}{4}+Q_{outer \, surface} \frac{R^2 \omega}{2} ]\hat{z} ##. Using ## Q_{total}=Q_{total \, heads}+Q_{outer \, surface} ##, the ## R^2 \omega ## factors out of everything, including ## \vec{L} ##, but we can not use ## Q_{total} ## in the final expression. The problem, if the hint of the professor is going to work, must either have the charge on the heads or on the outer surface, but not both at the same time. Anyway, that's what I got. Perhaps you can either confirm, or find that I made an algebraic error. [/QUOTE]
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Finding the relationship between magnetic momentum and angular momentum
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