Finding the resonant frequency

In summary: Under resonance, the impedance will be purely resistive and the voltage and current will be in phase.I'm not sure what you are asking, but at resonance the impedance will be purely resistive and the voltage and current will be in phase. The impedance will be at its minimum value, which is just R. Is that what you are asking?Yes, that's what I was asking.So, can you use that information to help find the relationship between L and C that will give the circuit a resonant frequency equal to 40π kHz?Yes, since the impedance will be purely resistive at resonance, we can set the imaginary part of the impedance to zero. This gives us the equation 0 = ω0L
  • #1
kl055
26
0
Finding L and C for which there is only one resonant frequency in cct

Homework Statement



an inductor in series with a paralle of (a capacitor and a resistor)
The inductor and resistor are fixed while C is variable

Z = sL + R/(1+RsC)

Find a value of L and C such that there is only one value of C for which there is a resonant freq

Homework Equations



R = 10k
resonant freq = 40k * pi

The Attempt at a Solution



Set Z = R at resonance and find that w^2RLC + jw(R^2C-L) = 0
at resonance, the bracket term becomes zero. But I am confused by the fact that the w is outside of the brackets. Do I just set R^2 C - L = 0 and find solve for L and C? But I only have one equation and two unknowns.
 
Last edited:
Physics news on Phys.org
  • #2
R = 10k
resonant freq = 40k * pi
... you mean R=10kΩ ?
... what is the resonant frequency: 40π kHz ?

How do you know that is the resonant frequency?

Z = sL + r/(1+RsC)
... do you have a value for the little r in that equation?
Should that be an R?

The question implies that there must be more than one resonant frequency - bourne out by the quadratic - I suspect there is a term missing there otherwise the resonant frequency is zero (DC case). However:

I only have one equation and two unknowns.
Is there only one combination of L and C that gives rise to a single resonant frequency or are there a range of them? Does the question ask you to find a unique value or a relationship? Is there more information? i.e. are you provided a target value for the resonant frequency as well?
 
Last edited:
  • #3
Sorry, I made a mistake in part 1 of my post. I corrected it now. r = R and the problem is to "Find a value of L and C such that there is only one value of C for which there is a resonant freq"

the resonant frequency is given in the problem statement.

Using only Locus diagrams and (trigonometry on those diagrams), I determined that L = 1/(2Rw) and C = R/(jw) or L = -1/(2Rw)) and C = -R/(jw). I am not sure if this is correct, but looking at the Locus diagrams it looked correct conceptually to me.

The second part of the problem is to verify my result by using equations only.


So I am given a target resonant frequency of 40k*pi rad/s and and that R = 10k ohms. I need to find L and C such that there is only one value of the variable capacitor for which the circuit is resonant. No other information is given.
 
Last edited:
  • #4
You have a resonant frequency, you have a relation between L and C ... the question kinda suggests that you should expect there to be two or more possible values of C that satisfy the resonance condition except for one particular value of L. Is that what you have?

(i.e. the resonance condition should be a quadratic in C.)
 
Last edited:
  • #5
Sort of. I had a circle in the impedance plane of the locus diagram. There were two intersections (when only the real part of the impedance exists at resonance) meaning that for a given value of L there were two values of C for which the circuit was resonant.

Then I shifted the circle up by L = 1/(2Rw) making the circle intersect at only one point (at the very bottom), meaning that for that particular value of L there was only one value of C for which the circuit is resonant. Similarly when I shifted downwards.

Thus when L = + or -1/(2Rw) there is only one value of C for which the circuit is resonant. I then found the corresponding C values using trigonometry.

Now I am required to do the same thing using only equations and no locus diagrams.
 
  • #6
Yes - and that is what you have shown us in post #1 and that is what I was referring to.
You have derived a relationship, from the equations, that must be satisfied for resonance to occur.
Is the relationship you have derived a quadratic in C?
 
  • #7
I suppose not since there is no C^2. So I need to derive another equation?
 
  • #8
I'd revisit the the way you derived the relation, yes.
Check your assumptions and go carefully.

[edit]
 
Last edited:
  • #9
Okay, thanks
 
  • #10
Basically you have worked out the impedance of the circuit, then used your knowledge of how the circuit behaves at resonance to work out the resonance condition on the impedance ... this gives you a relationship between the L R C and ω0 ... you are given R and ω0 so the relation is between L and C.

I think your equation for impedance is correct (I could be mistaken)
$$ z = j\omega L + \frac{R}{1+j\omega RC}$$
... so how does the circuit behave under resonance - in terms of relative phase (say)?
 

What is resonant frequency?

Resonant frequency is the natural frequency at which an object vibrates or oscillates with the least amount of external force applied. It is also known as the "preferred" or "natural" frequency.

How do you find the resonant frequency of an object?

The resonant frequency of an object can be found by subjecting it to a range of frequencies and measuring the response of the object. The frequency at which the object has the strongest response or vibration is the resonant frequency.

Why is finding the resonant frequency important?

Finding the resonant frequency of an object is important because it allows us to determine its natural frequency of vibration, which can have practical applications in various fields such as acoustics, engineering, and medicine. It also helps us to understand the behavior and characteristics of different objects.

What factors can affect the resonant frequency of an object?

The resonant frequency of an object can be affected by various factors such as the object's size, shape, material composition, and the amount of external force applied. Temperature, pressure, and humidity can also have an impact on an object's resonant frequency.

Can the resonant frequency of an object be changed?

Yes, the resonant frequency of an object can be changed by altering its physical properties such as its size, shape, or material composition. External forces can also change the resonant frequency, for example, by applying pressure or tension to the object.

Similar threads

Replies
10
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
5
Views
4K
  • Introductory Physics Homework Help
Replies
17
Views
375
  • Engineering and Comp Sci Homework Help
Replies
6
Views
3K
  • Engineering and Comp Sci Homework Help
Replies
14
Views
5K
  • Introductory Physics Homework Help
Replies
10
Views
539
  • Engineering and Comp Sci Homework Help
Replies
8
Views
4K
  • Engineering and Comp Sci Homework Help
Replies
1
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
3
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
6
Views
3K
Back
Top