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Physics
Classical Physics
Finding the spring constant of a rope
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[QUOTE="B0B, post: 6856610, member: 733581"] [B]TL;DR Summary:[/B] Kinetic Recovery Ropes are commonly used in the off road community to recovered stuck vehicles. But Kinetic ropes are rated by WLL (Working Load Limit) and MBS (Max Breaking Strength) with units in pounds. How can I uses those numbers + mass (weight)*V of my vehicle to guestimate the safe limit? The 7/8" Kinetic Recovery Rope like this [URL='https://yankum.com/collections/kinetic-recovery-ropes/products/python-kinetic-recovery-rope']yankum rope[/URL] is the most common size used for Jeeps, Broncos, and other SUVs. I apologize for English units but that's how ropes are sold and marketed. I've talked to the biggest rope suppliers and they have no idea how to compute the rope's spring constant, how to go size a rope by maximum momentum. All they know is ropes, and ropes are sold by WLL and MBS, which is easy to measure (WLL is just computed as a fraction of MBS). [LIST] [*]7/8" Kinetic Recovery Rope "Python" [ WLL 5,700-9,000 lbs] [MBS 28,600 lbs] [*]1" Kinetic Recovery Rope "Rattler" [WLL 6,700-11,200 lbs] [MBS 33,500 lbs] [*]1 1/4" Kinetic Recovery Rope "Mamba" [WLL 10,400 - 17,400 lbs] [MBS 52,300 lbs] [/LIST] I've seen several 7/8" Kinetic ropes broken by 4,500 Jeeps yanking on a vehicle stuck in the mud. My guess is they break from repeated pulls exceeding the elastic limit of the rope. I'd like to know how fast I can safely go with a given rope size. Assume the stuck rig is an immovable mass. I've yanked out several mud bogged rigs with my 1.25" rope where my 24K lbs winch was worthless. The winch just pulled me to the mud bog. Related link: [URL='https://www.physicsforums.com/threads/rope-wrapped-around-a-rod-belt-friction.1049878/']Rope wrapped around a rod - belt friction[/URL] For winch, the answer is N>9, ie 10 minimum wraps around the capstan (drum). [/QUOTE]
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Finding the spring constant of a rope
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