1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Finding the Velocity!

  1. Aug 27, 2008 #1
    You and a friend stand on a snow-covered roof. You both throw snowballs from an elevation of 14 m with the same initial speed of 13 m/s, but in different directions. You through your snowball downward, at 40° below the horizontal; your friend throws her snowball upward, at 40° above the horizontal. What is the speed of each ball when it is 5.0 m above the ground? (Neglect air resistance.)

    m/s (your snowball)
    m/s (your friend's snowball)

    15.7 m/s is what I keep getting... I did 13m/s sin 30 = 8.3 and.. i used that for Vf^2 = vi^2 + 2ax and used -9 for x and -9.81 for a...

    well 15.7 is not right... any thought?
  2. jcsd
  3. Aug 27, 2008 #2
    Why did you use -9 for x? First, find how long each snowball will be in the air.
  4. Aug 27, 2008 #3
    sin 30 or 40?
  5. Aug 27, 2008 #4


    User Avatar
    Homework Helper

    Remember velocity is composed of 2 components. What is the horizontal (x) component of velocity. That should stay the same with no air resistance. Then you have the vertical component to deal with. That is where you need to take into account the effect of gravity.
  6. Aug 27, 2008 #5
    i used -9 because that was the difference between 5-14? and its sin 40 :O

    so i find t and use Vi+at=Vf?

    i find t using x=Vit+1/2a(t)^2?
  7. Aug 27, 2008 #6


    User Avatar
    Homework Helper

    Yes that will give you the vertical velocity component. But the distance you should use is +9 as that is in the direction your velocity and acceleration is.

    Then you need to combine that with the horizontal component. (Velocity is a vector. You add the two vectors (x,y) together.)

    Edit: Btw there is nothing wrong with using the Vf2 = Vo2 +2aΔx you started out with.
    Last edited: Aug 27, 2008
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Finding the Velocity!
  1. Find the velocity (Replies: 1)

  2. Finding the Velocity (Replies: 2)

  3. Find the velocity (Replies: 6)

  4. Finding Velocity (Replies: 3)

  5. Finding Velocity (Replies: 14)