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## Homework Statement

Fireman weighs 100kg. He slides down a vertical pole with acceleration 3.0ms^-2.

a) Magnitude and direction of vertical force exerted by the pole on fireman?

## Homework Equations

f=ma

## The Attempt at a Solution

f=ma

f=100(3.0)

f=300N vertically up.

But the answer says that it is actually 680N vertically up, and I do understand how they came to this conclusion.

Can you please explain where to go beyond this point? Or point out a mistake I may have made? Thank you.