Fireman weighs 100kg. He slides down a vertical pole with acceleration 3.0ms^-2.
a) Magnitude and direction of vertical force exerted by the pole on fireman?
The Attempt at a Solution
f=300N vertically up.
But the answer says that it is actually 680N vertically up, and I do understand how they came to this conclusion.
Can you please explain where to go beyond this point? Or point out a mistake I may have made? Thank you.
I also replaced with acceleration with gravity, which did not work.