1. The problem statement, all variables and given/known data Fireman weighs 100kg. He slides down a vertical pole with acceleration 3.0ms^-2. a) Magnitude and direction of vertical force exerted by the pole on fireman? 2. Relevant equations f=ma 3. The attempt at a solution f=ma f=100(3.0) f=300N vertically up. But the answer says that it is actually 680N vertically up, and I do understand how they came to this conclusion. Can you please explain where to go beyond this point? Or point out a mistake I may have made? Thank you. I also replaced with acceleration with gravity, which did not work.