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Finding the z-score

  1. Sep 18, 2009 #1
    Human body temperatures are normally distributed with a mean of 98.20 and a standard deviation of 0.62.
    Find the z-score corresponding to a body temperature of 97.93.
    This is what I did.
    97.93 - 98.20 / .62
    I got -.44.

    WOuld a temperature of 99.71 be considered unusual?
    99.71 - 98.20 / .62.
    My answer 2.44. Yes because it's more than 2 SD.
     
  2. jcsd
  3. Sep 18, 2009 #2

    EnumaElish

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    Correct.
     
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