Human body temperatures are normally distributed with a mean of 98.20 and a standard deviation of 0.62.(adsbygoogle = window.adsbygoogle || []).push({});

Find the z-score corresponding to a body temperature of 97.93.

This is what I did.

97.93 - 98.20 / .62

I got -.44.

WOuld a temperature of 99.71 be considered unusual?

99.71 - 98.20 / .62.

My answer 2.44. Yes because it's more than 2 SD.

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# Finding the z-score

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