- #1

- 136

- 0

Thanks!

- Kamataat

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- Thread starter Kamataat
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- #1

- 136

- 0

Thanks!

- Kamataat

- #2

- 18

- 0

The mass of one mole of water = 18 grams.

Avogadro's = 6.02x10^23 molecules/mole

18gms/mole divided by 6.02x10^23 molecules/mole should work, if my chemistry isn't too rusty. The mole units will cancel each other, leaving you with units of gms/molecule.

Should get something like 3x10^-23 gm/molecule. Actually a little less, since I rounded all numbers off.

Please correct me (anyone) if I am incorrect!

Good luck.

Steve

- #3

- 136

- 0

All I know is Avogadro's number, the definition of a mole (# of atoms in 0.012kg of [itex]C^{12}[/itex]) and Clapeyron's equation.

Thanks anyway!

- Kamataat

- #4

- 505

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Am I missing something....?

- #5

- 91

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Given only avogadro's number, you definately need to have the molar mass to find the number of molecules.

- #6

- 2,210

- 1

[tex] \left(\frac{18.02 g}{1 mol}\right) \left(\frac{1 mol}{6.02 \times 10^{23} molecules}\right) = \left(\frac{ x grams}{ 1 molecule }\right) [/tex]

- #7

- 396

- 2

Smith basically used this then multiplied by one mole then divided by one mole.

- #8

- 136

- 0

Thanks everyone for making this clear for me!!!

- Kamataat

- Kamataat

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