# Finding Vc

1. Sep 23, 2009

### xpack

http://img41.imageshack.us/img41/416/32650113.png [Broken][/URL]

Relevant equations ?

I know area under the curve is 660
But I dont know what the question is asking

Last edited by a moderator: May 4, 2017
2. Sep 23, 2009

### waht

find Vc at t = 10 microseconds?

3. Sep 24, 2009

### xpack

Yeah, is it just 44*.10?

4. Sep 24, 2009

### waht

No, consider what you are doing with the integral - what are the units of the area under the curve? Knowing that, recall the relation between capacitance and charge.

5. Sep 24, 2009

### xpack

Yeah Q=VC
As for the units under the area of curve, I dont know mA/microsecs?

6. Sep 24, 2009

### waht

The area is under the curve represents mA * uS

but an amp A = C / s, so the area is the charge being deposited in the capacitor, so you got Q.

7. Oct 1, 2009

### Mr.Green

Look at the Hint carefully. It says that you should integrate I(t) over a period of time to find the voltage. If you want to integrate you should have a function, i.e. current as a function of time.
So...obtain the relation between the current and the time. Then integrate it over the desired period to obtain the voltage.