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Finding Vector angle

  1. Jan 31, 2005 #1
    Hi,
    There is an aircraft moving at 300KM/h from its destination due north from an airport. It has to fly to the other airport(North) for 90KM.

    The wind is blowing at 80KM/h from West to east.

    At what angle must the aircraft fly to make its destination.


    From my work out I found it to be N15.467W.

    here is some work out.

    let O=V wind

    Let H=V aircraft

    O/H=sin

    Sin Thita=O/H
    =80/300
    Thita=Sin^1(80/300)
    =Sin^-1(0.2667)
    =15.467


    Does this look right?
     
  2. jcsd
  3. Jan 31, 2005 #2
    I got 14.9 degrees.
     

    Attached Files:

  4. Jan 31, 2005 #3

    Did you use 300 as H or A?

    The velocity is relative to Air.


    I also had 14.93 but that was when I used 300 as A.
     
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