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Finding Voltage in a Circuit

  1. Feb 21, 2008 #1
    1. I made a quick sketch
    Find V1 and V2

    3. Is there an easier way to do this question without applying mesh analysis, because this question was in my chapter 2 (intro to KVL/KCL), but i cannot think of a way to find this unless i use mesh analysis. Any advice
  2. jcsd
  3. Feb 21, 2008 #2
    Well assuming I'm doing it right of course, you wouldn't need any simultaneous equations or anything, that'd be over complicating it, just need KCL really

    so at the node above the 20 and 5 k resistors(or the equivalent 4k resistor!)you have 10 milliamps flowing in, and you need 10 mA flowing out, obtained with a voltage drop across that 4 k of just V=IR=10*4=40 Volts

    You can check to see that puts 8 mA across the 5 k resistor and 2 across the 20 k, for a total of 10 mA
  4. Feb 21, 2008 #3
    the answer for v1 = 20 V

    not 40 V

    so hmmmmmmmm
  5. Feb 21, 2008 #4
    ok, so what you basically have are two resistors in series, and those two resistors(with eq. resistance of 4k) are in parallel with the other two resistors which I mentioned have an equiv. resistance of 4k as well

    Since they're in parallel the current splits down both paths and equal amounts both ways since the resistances are ultimately equal, sooo it's actually V=I*R=5*4=20Volts
  6. Feb 22, 2008 #5


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    If you know V1, then all you need to do is "voltage-divide" to find V2.
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