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Finding volume by integration

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Find the volume of the solid formed when the region bounded by the curves y=x3, y=1, and x=0 is rotated about the y-axis, use washer AND shell methods

Disc/Washer:
Ωx2dy = Ω(y1/3)2dy = Ωy2/3dy
Volume:
V = 0∫1 Ωy2/3dy = Ω{(3y5/3)/5} = 3Ω/5


Shell:
2Ωy(x)dx = 2Ωx(x3)dx = 2Ωx4dx
Volume:
V = 0∫1 2Ωx4dx = 2Ω{(x5)/5} = 2Ω/5


Obviously this question seems simple enough but I'm finding different answers so I'm going wrong somewhere. Any help is appreciated
 

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LCKurtz
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Find the volume of the solid formed when the region bounded by the curves y=x3, y=1, and x=0 is rotated about the y-axis, use washer AND shell methods

Disc/Washer:
Ωx2dy = Ω(y1/3)2dy = Ωy2/3dy
Volume:
V = 0∫1 Ωy2/3dy = Ω{(3y5/3)/5} = 3Ω/5


Shell:
2Ωy(x)dx = 2Ωx(x3)dx = 2Ωx4dx
Volume:
V = 0∫1 2Ωx4dx = 2Ω{(x5)/5} = 2Ω/5


Obviously this question seems simple enough but I'm finding different answers so I'm going wrong somewhere. Any help is appreciated
For a shell you want ##2\pi x(y_{upper}-y_{lower})## in the integrand. And use ##\pi## instead of ##\Omega##.
 

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