Finding volume

  • Thread starter real10
  • Start date
  • #1
real10
39
0
x^2+y^2+z^2=4
(x+2)^2+(y-1)^2+(z+2)^2=4

find volume inside both.
thanks,
 

Answers and Replies

  • #2
balakrishnan_v
50
0
Just draw and integrate.You will get
[tex]\frac{11 \pi}{12}[/tex]
 
  • #3
real10
39
0
i meant the volume of intersection due to those spheres.(common to both)
any details like what are the bounds for the integral u set up and which one..

thanks again,
 
  • #4
amcavoy
665
0
I may be wrong, but try to find the region first by setting both equations equal. The "height" of each point in the intersection will be equal to the first equation minus the second.

[tex]z_1=\sqrt{2-x^2-y^2}[/tex]

[tex]z_2=\sqrt{4-(x+2)^2-(y-1)^2}-2[/tex]

[tex]V=\iint\limits_{D}\left(z_1-z_2\right)dA[/tex]
 

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