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Homework Help: Finding work done by a escalor

  1. Nov 2, 2008 #1
    1. The problem statement, all variables and given/known data
    http://img252.imageshack.us/my.php?image=heyheygw0.jpg
    Mass=57.1 Kg
    Distance 69.5 m
    G= 9.8
    Theta= 34.9
    So I'm trying to find the amount of work done on mass.

    2. Relevant equations
    F=ma
    Work=Fcos(theta)D


    3. The attempt at a solution
    Okay so i started out finding Force by newtons 2nd law.
    F=ma
    f=57.1(9.8)
    F=559.58
    Okay so then I went with force to the work fomula.
    Work=559.58cos(34.9)69.5
    and that gave me 31896.37
    but this answer proved to be incorrect?
     
  2. jcsd
  3. Nov 2, 2008 #2

    Astronuc

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    Staff Emeritus
    Science Advisor

    Why cos(theta)? Over what height is mass (or weight) lifted?
     
  4. Nov 2, 2008 #3
    good question.
    sin would prehaps be more fitting =)
     
  5. Jul 12, 2010 #4
    I have a similar problem like this so if I was to solve this problem would it go like this:
    Work=Fsin(theta)D

    ???
     
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