# Finding x and y components

1. Jan 27, 2009

### spokorne

I've been stuck on this problem for too long and need help. Please explain the answer if possible.

F1 has a magnitude of 8.80 n and is directed at an angle of $$\alpha$$= 65.0 above the negative x axis in the second quadrant. F2 has a magnitude of 6.40 N and is directed at an angle of $$\beta$$ = 53.3 below the negative x axis in the third quadrant.

What is the x component Fx of the resultant force?

What is the y component Fy of the resultant force?

What is the magnitude F of the resultant force?

What is the angle $$\gamma$$ that the resultant force forms with the negative x axis? In this problem, assume that positive angles are measured clockwise from the negative x axis.

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2. Jan 27, 2009

### LowlyPion

Welcome to PF.

What have you attempted?

3. Jan 27, 2009

### spokorne

i tried making them into triangles and then using the lengths as the force. then i figured out the upward force and minused the downard force to find the total vertical force but it isn't right

4. Jan 27, 2009

### LowlyPion

Maybe if you calculated the x,y components of the vectors it would be a little easier?

5. Jan 27, 2009

### spokorne

how do you go about doing that?

6. Jan 27, 2009

### LowlyPion

The dog on a leash is an example at the bottom of this link:
http://www.glenbrook.k12.il.us/GBSSCI/PHYS/CLASS/vectors/u3l1e.html [Broken]

Last edited by a moderator: May 3, 2017
7. Jan 27, 2009

### spokorne

That's what I did previously and then then i found the difference in the two and it was incorrect

8. Jan 27, 2009

### LowlyPion

I can't see your effort, so you should check that you have the correct sign of the x components when you add them and the y components.

After you have added them then you use what Pythagoras taught.