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Finding x and y components

  1. Jan 27, 2009 #1
    I've been stuck on this problem for too long and need help. Please explain the answer if possible.

    F1 has a magnitude of 8.80 n and is directed at an angle of [tex]\alpha[/tex]= 65.0 above the negative x axis in the second quadrant. F2 has a magnitude of 6.40 N and is directed at an angle of [tex]\beta[/tex] = 53.3 below the negative x axis in the third quadrant.


    What is the x component Fx of the resultant force?

    What is the y component Fy of the resultant force?

    What is the magnitude F of the resultant force?

    What is the angle [tex]\gamma[/tex] that the resultant force forms with the negative x axis? In this problem, assume that positive angles are measured clockwise from the negative x axis.
     

    Attached Files:

  2. jcsd
  3. Jan 27, 2009 #2

    LowlyPion

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    Welcome to PF.

    What have you attempted?
     
  4. Jan 27, 2009 #3
    i tried making them into triangles and then using the lengths as the force. then i figured out the upward force and minused the downard force to find the total vertical force but it isn't right
     
  5. Jan 27, 2009 #4

    LowlyPion

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    Maybe if you calculated the x,y components of the vectors it would be a little easier?
     
  6. Jan 27, 2009 #5
    how do you go about doing that?
     
  7. Jan 27, 2009 #6

    LowlyPion

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  8. Jan 27, 2009 #7
    That's what I did previously and then then i found the difference in the two and it was incorrect
     
  9. Jan 27, 2009 #8

    LowlyPion

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    I can't see your effort, so you should check that you have the correct sign of the x components when you add them and the y components.

    After you have added them then you use what Pythagoras taught.
     
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