Finding x and y components

  • Thread starter spokorne
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  • #1
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I've been stuck on this problem for too long and need help. Please explain the answer if possible.

F1 has a magnitude of 8.80 n and is directed at an angle of [tex]\alpha[/tex]= 65.0 above the negative x axis in the second quadrant. F2 has a magnitude of 6.40 N and is directed at an angle of [tex]\beta[/tex] = 53.3 below the negative x axis in the third quadrant.


What is the x component Fx of the resultant force?

What is the y component Fy of the resultant force?

What is the magnitude F of the resultant force?

What is the angle [tex]\gamma[/tex] that the resultant force forms with the negative x axis? In this problem, assume that positive angles are measured clockwise from the negative x axis.
 

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Answers and Replies

  • #2
LowlyPion
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Welcome to PF.

What have you attempted?
 
  • #3
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i tried making them into triangles and then using the lengths as the force. then i figured out the upward force and minused the downard force to find the total vertical force but it isn't right
 
  • #4
LowlyPion
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Maybe if you calculated the x,y components of the vectors it would be a little easier?
 
  • #5
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how do you go about doing that?
 
  • #6
LowlyPion
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The dog on a leash is an example at the bottom of this link:
http://www.glenbrook.k12.il.us/GBSSCI/PHYS/CLASS/vectors/u3l1e.html [Broken]
 
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  • #7
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That's what I did previously and then then i found the difference in the two and it was incorrect
 
  • #8
LowlyPion
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I can't see your effort, so you should check that you have the correct sign of the x components when you add them and the y components.

After you have added them then you use what Pythagoras taught.
 

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