I've been stuck on this problem for too long and need help. Please explain the answer if possible. F1 has a magnitude of 8.80 n and is directed at an angle of [tex]\alpha[/tex]= 65.0 above the negative x axis in the second quadrant. F2 has a magnitude of 6.40 N and is directed at an angle of [tex]\beta[/tex] = 53.3 below the negative x axis in the third quadrant. What is the x component Fx of the resultant force? What is the y component Fy of the resultant force? What is the magnitude F of the resultant force? What is the angle [tex]\gamma[/tex] that the resultant force forms with the negative x axis? In this problem, assume that positive angles are measured clockwise from the negative x axis.
i tried making them into triangles and then using the lengths as the force. then i figured out the upward force and minused the downard force to find the total vertical force but it isn't right
The dog on a leash is an example at the bottom of this link: http://www.glenbrook.k12.il.us/GBSSCI/PHYS/CLASS/vectors/u3l1e.html
I can't see your effort, so you should check that you have the correct sign of the x components when you add them and the y components. After you have added them then you use what Pythagoras taught.