hi everyone ,, got this question and I need the idea today if possible:
Find the x-coordinate of the point on the graph of y = x^3 where
the tangent line is parallel to the secant line that cuts the curve at x = -1 and x = 1.
The Attempt at a Solution
i got the derivative and then the tangent line equaled m=3 and then i got this equation:
y=3x+2 so my x coordinates are (1,5) (-1,-1) ,, and I think it's wrong because (-1,-1) is not parallel ,, so how to get it and then what should i do to get the coordinates ,,