- #1

terryfields

- 44

- 0

answers being kerT={uEU:T(u)=0} and imT=T(U)={T(u):uEU}

then there's a second part to the question asking me to state the definitions of rank and nullity if this is a finite dimensional space, what does finite dimensional mean? is this just the normal definitions of rank and nullity i.e the dimension of the kernal and the dimension of the image?