Finite Field Extensions

In summary, the conversation discusses the proof that if alpha is algebraic over a field F and [F(alpha):F] is odd, then F(alpha^2) = F(alpha). The conversation also mentions the Tower Law, which states that for any fields L, K, and M, [M:L] = [M:K][K:L]. However, the problem can be solved without invoking the Tower Law.
  • #1

Homework Statement


Let F be a field, and suppose that alpha is algebraic over F. Prove that if [F(alpha):F] is odd, then F(a^2)=F(a). {For those unfamiliar with notation [] denotes degree of extension and F(alpha) means F adjoined with alpha.)


The Attempt at a Solution


Since [F(alpha):F] is odd the basis of F(alpha) consists of an odd number of elements. We also know that b in F(alpha) has the form c_0+c_1alpha+c_2alpha^2+...+c_n-1alpha^(n-1). I really have no idea how to proceed from here. Help would be much appreciated. Thanks.
 
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  • #2
First of all, have you learned the Tower Law yet (i.e., if [tex] L \subseteq K \subseteq M [/tex] are fields, then [tex] [M : L] = [M : K] [K : L] [/tex])?

If you understand this, then the problem is relatively easy. It should be pretty obvious that [tex] F(\alpha^2) \subseteq F(\alpha) [/tex]. Furthermore, [tex] F(\alpha^2) = F(\alpha) [/tex] if and only if [tex] [F(\alpha) : F(\alpha^2) ] = 1 [/tex]. Why is it true that if [tex] [F(\alpha) : F(\alpha^2)] \neq 1 [/tex], then [tex] [F(\alpha) : F(\alpha^2)] = 2 [/tex]? Using the tower law, why would the latter contradict your assumptions about [tex] [F(\alpha):F] [/tex]?
 
  • #3
Thanks for the help, but sorry we haven't learned about the "tower law." Can you help me with the part where you said that [F(a):F(a^2)]=2 if not 1.
 
  • #4
Well, for any field [tex] K [/tex] and any [tex] \beta [/tex], the degree of [tex] K(\beta) [/tex] over [tex] K [/tex] is the degree of the minimal polynomial of [tex] \beta [/tex] over [tex] K [/tex]. We know that [tex] \alpha [/tex] satisfies the polynomial [tex] f(x) = x^2 - \alpha^2 [/tex] with coefficients in [tex] F(\alpha^2) [/tex]; hence, the minimal polynomial of [tex] \alpha [/tex] over [tex] F(\alpha^2) [/tex] must divide [tex] f(x) [/tex]. Since the degree of [tex] f(x) [/tex] is 2, this implies that the degree of [tex] \alpha [/tex] over [tex] F(\alpha^2) [/tex] is less than or equal to 2.

The tower law is the following: For any fields [tex] L \subseteq K \subseteq M [/tex], we have [tex] [M:L] = [M:K] [K:L] [/tex]. (I'm a little surprised that you were assigned this question if you haven't covered this, to be honest; maybe they want you to derive a special case of the tower law yourself?)
 
  • #5
There is no need to invoke the tower law - you can prove this entirely constructively. It would be by proving elementary results like this that would lead you to conjecturing and proving the tower law in fact. Invoking the tower law would be exactly like invoking Lagrange's theorem to show that if |G| is odd then o(x)=o(x^2) for x in G.
 

What are finite field extensions?

Finite field extensions are mathematical structures that extend the properties of finite fields. They are used in abstract algebra and number theory to study the properties of polynomials and algebraic equations.

What is the degree of a finite field extension?

The degree of a finite field extension is the number of elements in the field. It is also known as the order of the field. The degree of a finite field extension is always a power of a prime number.

How are finite field extensions represented?

Finite field extensions are typically represented using a notation such as GF(p^n), where p is the characteristic of the field and n is the degree of the extension. For example, GF(2^8) represents the finite field extension with characteristic 2 and degree 8.

What are some applications of finite field extensions?

Finite field extensions have many applications in cryptography, coding theory, and error-correcting codes. They are also used in the construction of mathematical structures such as finite geometries and designs.

How do I perform arithmetic operations in finite field extensions?

Arithmetic operations in finite field extensions follow specific rules and properties, which are based on the underlying field. Addition, subtraction, multiplication, and division in finite field extensions are performed using modular arithmetic and the properties of finite fields.

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