[itex]\int^{\infty}_{1}[/itex][itex]\frac{1}{e^{t}-1}dt[/itex](adsbygoogle = window.adsbygoogle || []).push({});

[itex]= -ln(e - 1) + 1 [/itex]

Not sure how to get the +1 part from infinity, seems like it should be infinity, i.e.

[itex] ln(e^{\infty} -1) = ??? [/itex]

Any help appreciated, thanks.

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# Finite Integral, not sure why

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