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Solve Finite Potential Well: Schrödinger Eqn. & k=qtan(q*a)
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[QUOTE="feynwomann, post: 4940985, member: 498256"] Oh it totally makes sense now. I forgot that my teacher said there was a mistake in the exercise. It's supposed to be B = 0. I didn't think of dividing the equations (I had actually done the first step, but didn't see how I could take it further). Anyway, thanks for the help! [/QUOTE]
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Solve Finite Potential Well: Schrödinger Eqn. & k=qtan(q*a)
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