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I am looking at a scattering example in my book. A particle is incident from the left with energy E > Vo. The barrier is of width L, and located between x = 0 and x = L.

The solutions to the time-independent Schrodinger equation in eacch of the regions comprising the left and right of the barrier and inside the barrier are:

[tex]\psi(x) = G e^{ik_{1} x} + H e^{-ik_{1} x }.......... x < 0[/tex]

[tex]\psi(x) = I e^{ik_{2} x} + J e^{-ik_{2} x }............0 \leq x \leq L[/tex]

[tex]\psi(x) = K e^{ik_{1} x} + L e^{-ik_{1} x } ...........x > L [/tex]

The example in the book gives the transmission coefficient [tex] T = \frac{|K|^{2}}{|G|^{2}} [/tex] but my question is what ratio gives the reflection coefficient?

I thought [tex] R = \frac{|H|^{2}}{|G|^{2}} [/tex] but does the constant [tex]J[/tex] play any part in determining the reflection coefficient?

Thanks

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# Finite Square Barrier

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