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I Finite square well

  1. Mar 19, 2017 #1
    I am not sure how is it possible that asymetric potential well does not have bond states if ##E<U_1<U_2##. In symmetric case solution always exists. Why this is a case?
     
  2. jcsd
  3. Mar 19, 2017 #2

    Nugatory

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    Staff: Mentor

    I may be misunderstanding the question here.... The asymmetric finite square well does have bound state solutions.
     
  4. Mar 19, 2017 #3
    But not always. Right? Symmetric square well always has bound state solution.
     
  5. Mar 20, 2017 #4
    For square (asymmetric) potential well an explicit equation with respect to energies of bound states is not difficult to derive. The existence of at least one bound state follows from that equation almost immediately.
     
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