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First degree ode (cosh/sinh)

  • Thread starter bigevil
  • Start date
  • #1
79
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Homework Statement



[tex]\frac{dy}{dx} = \frac{cosh x cos y + cosh y sin x}{sinh x sin y - sinh y sin x}[/tex]

I'm really stuck at this one. I don't even know where to start, but I hope that a substitution (ie u = f(x,y)) might be able to put this in a separable form. Any hints please??

Other roads:

1. Hyperbolic cosine/sine identities?

2. Expressing as powers of e?
 

Answers and Replies

  • #2
392
0
Is there a typo? It's almost exact. The sin x in the numerator looks out of place.
 
  • #3
This is an exact equation.

dy/dx = Numerator/Denominater

D dx - N dy =0

[tex]\partial[/tex]D/[tex]\partial[/tex]y=[tex]\partial[/tex]N/[tex]\partial[/tex]x

u (nearly)=D dx + N dy
 

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