The switch in the diagram below has been open for a long time prior to t = 0; then it closes at t = 0 and opens again at t = 105 µs. Find: 1. Ix(75 µs), 2. Vx(75 µs), 3. Ix(190 µs), 4. Vx(190 µs). Attached is the diagram of the circuit and its answers. so i understand how to get questions 1 and 2, but for 3 and 4 I am stuck. i found the voltage of the capacitor at time 105µs so I am assuming I use that voltage as the initial condition to questions 3 and 4. I also know that the time constant(tau2) will be different as it will only be the C and R1. these are the values i am calculating thus far. vx(105us) = 7.1467V Tau2 = 33n*3900 vx(190us) = 7.1467e^(-190us/tau2) << i have a feeling i have done something wrong here thanks guys!