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First order DE initial value

  1. Oct 24, 2011 #1
    The problem:

    dx(1-y^2)^1/2=dy(1-x^2)^1/2

    y(0)=3^(1/2)/2

    My attempt:

    I separated the variables and integrated, and came up with

    sin^-1(x)+c=sin^-1(y)

    This is where i am stuck. any suggestions? did I run astray anywhere?
     
  2. jcsd
  3. Oct 25, 2011 #2
    You seem to be on the right track. Now given the initial value, plug in 0 for x and 3^(1/2)/2 for y and solve for C. You should take it from there.
     
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