Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

First order DE initial value

  1. Oct 24, 2011 #1
    The problem:

    dx(1-y^2)^1/2=dy(1-x^2)^1/2

    y(0)=3^(1/2)/2

    My attempt:

    I separated the variables and integrated, and came up with

    sin^-1(x)+c=sin^-1(y)

    This is where i am stuck. any suggestions? did I run astray anywhere?
     
  2. jcsd
  3. Oct 25, 2011 #2
    You seem to be on the right track. Now given the initial value, plug in 0 for x and 3^(1/2)/2 for y and solve for C. You should take it from there.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: First order DE initial value
  1. Nonlinear first order DE (Replies: 22)

  2. First Order DE (Replies: 2)

Loading...