First order DE initial value

  • Thread starter Eastonc2
  • Start date
  • #1
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Main Question or Discussion Point

The problem:

dx(1-y^2)^1/2=dy(1-x^2)^1/2

y(0)=3^(1/2)/2

My attempt:

I separated the variables and integrated, and came up with

sin^-1(x)+c=sin^-1(y)

This is where i am stuck. any suggestions? did I run astray anywhere?
 

Answers and Replies

  • #2
186
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You seem to be on the right track. Now given the initial value, plug in 0 for x and 3^(1/2)/2 for y and solve for C. You should take it from there.
 

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