(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Solve: (2t+x) dx/dt + t = 0

2. Relevant equations

y' +p(X)y = q(x)

and y(x) = ([tex]\int[/tex]u(x)q(x) + c)/u(x)

where u(x) = e^{[tex]\int[/tex]p(x)dx}

Note this u(x) is 2 to the power of the integral of p(x)

3. The attempt at a solution

(2t+x) dx/dt + t = 0 becomes:

dx/dt + t/(2t+x) = 0 by dividing through by (2t+x)

However, now I don't know how to separate t and x in the second term.

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# First order differentials

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