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## Homework Statement

(3xy^2+4y)dx+(3x^2y+4x)dy=0

## Homework Equations

## The Attempt at a Solution

So First I checked if both equations were exact. I took the derivative of 3xy^2+4y and also derivative of the other and they were both equal so the equation is exact.

I took the 3xy^2+4y and integrated it with respect to x. And then I differentiated it to y.

I got 3x^2y+4x out of it. The problem is that it is exactly the same as the one from the originally equation so I did not ending up finding C.

Did I do something wrong?

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