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First order system ODE, complex root

  1. Dec 3, 2012 #1
    Hi.

    For first order system ODE, complex root.
    y'=Ay, where A is a 2by2 matrix. I am assuming the roots are complex. After finding the eigenvalue (complex conjugate) and their eigen-vectors (which come in a form of complex conjugate again), we plug into the solution y=ζexp(λt), where λ is egenvalue and ζ is its corresponding eigenvector. And Since λ is complex, we apply euler's formula.And at the end, we get to the part
    y= u(t) + i*v(t).

    I don't understand why both u(t) and v(t) are solution to the system. u(t) is clear. But v(t) is not. what happen to its imaginary number?


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    Last edited: Dec 3, 2012
  2. jcsd
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