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54) A small fish is dropped by a pelican that is rising steadily at 0.50 m/s.

a) After 2.5 s, what is the velocity of the fish? Ans: -24 m/s

b) How far below the pelican is the fish after 2.5 s? Ans: 31m

My Work/Question:

The fish would be moving at the same velocity as the pelican, which equals the (Vi). The Accel would equal -9.81 m/s^2 due to gravity.

I used Vf = (Vi) + (A)(T) to find the velocity of the fish.

My question on B: Would I use the.... delt X = (Vi)(t) + (1/2)(A)(T)^2....formula for B?

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# Homework Help: Fish and Pelican Problem

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