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Q. There is a fish in a spherical fish bowl of radius r filled with water. The fish is at a distance l from the surface of the tank. An observer in air views the fish at a distance d from the tank.
Please see the attachment for the image.
I am supposed to find the optical power and focus length of the waterair interface, the magnification power of the fish tank and an expression for the distance (L) between the obsever and optical image of the fish.
Here are the attempts I have made:
Optical power = (n1n2)/(r)
Focus Length = f'=n2/P = n2r/(n1n2)
I used f' because I think it is a virtual image?
Magnification Power = (Image Distance/Object Distance) =((Ld)/r)
L=(n1/r + n2/l)
Can anyone tell me if these are correct or if I am at least going along in the right direction?
Please see the attachment for the image.
I am supposed to find the optical power and focus length of the waterair interface, the magnification power of the fish tank and an expression for the distance (L) between the obsever and optical image of the fish.
Here are the attempts I have made:
Optical power = (n1n2)/(r)
Focus Length = f'=n2/P = n2r/(n1n2)
I used f' because I think it is a virtual image?
Magnification Power = (Image Distance/Object Distance) =((Ld)/r)
L=(n1/r + n2/l)
Can anyone tell me if these are correct or if I am at least going along in the right direction?
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