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Fixed points

  • Thread starter morbello
  • Start date
  • #1
73
0
ive got a question on how to get a fixed point. on the equation for.

[tex]\frac{1}{8}X^2+\frac{11}{8}X+\frac{1}{2}[/tex]

do you find the two factors to get the fixed points. or run the equation though a quadratic formula to get the fixed points.

i have an = which is x^2-3X-4=0 but i dont know how the fraction 11/8X =3X in the equation.

Homework Statement




Homework Equations





The Attempt at a Solution


A fixed point for a function, f, is a value of x such that f(x)= x.
Here
[tex]f(x)= \frac{1}{8}X^2+\frac{11}{8}X+\frac{1}{2}= x[/tex]
The easiest way to handle the fractions is to multiply the entire equation by 8:
[tex]x^2+ 11x+ 1= 8x[/tex]
or
[tex]x^2+ 3x+ 1= 0[/tex]
 
Last edited by a moderator:

Answers and Replies

  • #2
Tom Mattson
Staff Emeritus
Science Advisor
Gold Member
5,500
7
Yes, that's how you do it. But I wouldn't use both [itex]X[/itex] and [itex]x[/itex] for the variable. Use the same symbol in each instance.
 
  • #3
73
0
thank you for your help.
 

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