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Flexibility 2

  1. May 3, 2012 #1
    1 = √(1)
    = √(-1)(-1)
    = (√-1)(√-1)
    = i.i
    = i[itex]^{2}[/itex]
    = -1
    Is this a correct equation??
    anythings wrong with this?
    i think theoretically it is correct but it seems like
    √(1) = √(-1)(-1)
    √(1) = √(1)(1) also!!
    so how to explain this??
     
  2. jcsd
  3. May 3, 2012 #2


    Squaring is a double branched complex variable function, and thus "usual" properties in real numbers can fail miserably.

    In this case the problem appears in the third equality: it isn't true without imposing certain restrictive conditions.

    DonAntonio
     
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