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Flight time approximations

  1. Nov 11, 2013 #1
    Hi, I'm basically trying to figure out if there's a quick way to approximate the flight time of something thrown downwards off a cliff.

    If you throw a projectile off a cliff with height H > 0 above the ground, there are 3 cases:

    v_y > 0
    v_y = 0 (thrown horizontally off the cliff)
    v_y < 0

    For v_y > 0, it takes about v_y/10 seconds = t1 to reach the peak above the cliff and the new height is about H + (v_y)^2/20. Since v_y = 0 at the peak, it's like a freefall question from height H + (v_y)^2/20, so you can set H + (v_y)^2/20 = 5t^2, t2 = sqrt(H+(v_y)^2/20) and the total flight time is about t1 + t2.

    If v_y = 0 then it's free fall and H = 5t^2 so t = sqrt(H/5).

    For v_y < 0 (thrown downwards off a cliff), how can I approximate it without doing a quadratic equation? I guessed t1 + t2 - 1 but I'm not sure if that's right.

    Thanks!
     
  2. jcsd
  3. Nov 11, 2013 #2

    TumblingDice

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  4. Nov 12, 2013 #3

    CWatters

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    Homework Helper

    If you assume constant acceleration the SUVAT equation..

    s = ut + 0.5at2

    (where u is the vertical velocity)

    applies apply to all three cases.

    One approximation you could make is to assume u is small.
     
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