Floating Rock Raft

1. Aug 11, 2012

Can anyone answer a couple of questions about the new floating rock raft off New Zealand ?

How much mass does it contain ?

Where is it headed ? ( or will it disperse ? )

2. Aug 11, 2012

Staff: Mentor

Please post a link, do not make members hunt for the source.

3. Aug 11, 2012

Bobbywhy

It has just been discovered around 09 August and there have been not published estimates of its total mass, as far as I know.

http://www.bbc.co.uk/news/science-environment-19207810
http://news.yahoo.com/bizarre-rock-ice-shelf-found-pacific-104349304.html [Broken]

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Last edited by a moderator: May 6, 2017
4. Aug 11, 2012

Last edited: Aug 11, 2012
5. Aug 12, 2012

davenn

well time for you to try some maths ;)
you have some of the info, and wiki will provide the rest

its 26,000 sqr km x ~ 600mm (0.6metre thick)

wiki gives an example of ~ 0.25 g / cubic cm for pumice

work out the volume from the first 2 measurements then multiply it by the density

watch your values I would suggest get everything into cubic metres rather than trying to work with km, cm etc

Dave

6. Aug 12, 2012

Last edited: Aug 12, 2012
7. Aug 13, 2012

davenn

yup some bad maths there I think ;)

26,000 sqr km = 26,000,000 sqr metres ( 26 million) x 0.6 metres = 15,600,000 (15.6 million) cubic metres

0.25g / 1ccm => 2.5g / 10 ccm => 25g / 100ccm (ccm = cubic cm) 100ccm = 1 cubic metre

25g = 0.025kg

15,600,000 cubic metres x 0.025kg = 390,000 kg = 390 tonnes ( 1 Tonne = 1000kg)

some one check my maths please :)

Dave

8. Aug 13, 2012

billiards

Those numbers aren't right. I reckon:

26,000 sqr km = 26,000,000,000 sqr metres

0.25g / 1ccm = 250 kg/m3

EDIT: Imagine a cubic metre of rock. Now how much does that weigh? 25 grams? No way!

9. Aug 13, 2012

davenn

crap, I really screwed up my calcs.. doh.... I'll bow to your better maths, no wonder I failed school cert maths twice haha

after using some online convertors I agree with your m2
I will work on the rest as well

Dave

Last edited: Aug 13, 2012
10. Aug 13, 2012

davenn

using online calculators

gosh am getting such huge numbers its freaky haha
I need to work through this for my own understanding/sanity please correct me if I go wrong

so 10,000 cm2 = 1 metre2

therefore 10,000 x 10,000 x 10,000 cm = 1 m3

now here's something that has always caught me out....
thats 1 with 12 0's is that the same as 1 x 1012 or 1 x 1011 .... I was thinking 11

Dave

11. Aug 13, 2012

billiards

Hi Dave

1 m = 100 cm
1 m2 = m * m = 100 cm * 100 cm = 10,000 cm2

You got that bit right.

Next:

1 m3 = m * m * m = 100 cm * 100 cm * 100 cm = 1,000,000 cm3

You slipped up with that bit.

Incidentally: 1 with 12 0's is the same as 1012.

This stuff is not really maths. It's just working with units. Try to picture a square metre, then imagine how many square cm would fit inside it, then try to imagine a cubic metre and image how many cubic cm would fit inside it. The maths just drops out of the mental picture.

Cheers

12. Aug 13, 2012

davenn

OK thanks

yeah something that will trip me up easily haha
i will continue working through this in this thread cuz I eventually want to confirm for myself the cubic volume and mass of the pumice .... besides there may be others that learn something too haha

OK so we have 26,000,000,000 metres2 and for an avg lets just pick 0.5 m thick = 13,000,000,000 m3

now the fun of converting 0.25g / cm3 to kg / m3

0.25 x 1,000,0003 (1m3) = 250,000g / 1m3 = 250kg / 1m3
which is what you said earlier, billiards :)

so 13,000,000,000 m3 x 250kg / 1m3 = 3,250,000,000,000 kg = 3,250,000,000 metric Tonnes

OK how did I go that time ? :)

Dave

13. Aug 14, 2012

good that time :) - I use a depth 0.6 to get the 3.9 billion verse 0.5 to get 3.2

Last edited: Aug 14, 2012
14. Aug 14, 2012

billiards

Good but the thickness assumption is probably whacky.

One article says the pumice fragments are golf ball sized.

Now golf balls have a diameter of about 5 cm. So I would scale down your answer by a factor of 10 (dave).

Then there is the issue that this thickness is not uniform over the areal extent. You could make another assumption -- e.g. close hexagonal packing -- to account for the gaps in between the pumice fragments: multiply your answer again by 0.74.

15. Aug 14, 2012

davenn

yes agreed, the calcs were for a uniform thickness/density, but at least I finally got my units and maths sorted out haha

D

16. Aug 15, 2012

billiards

Awesome. Glad to be able to help out