The average flow rate in the Niagara River is 6.0 x 10^6 kg/s and the water drops 50 m over Niagara falls. If all this energy could be harnessed to generate hydroelectric efficiency at 90% efficiency, what would be the electric power output?
The Attempt at a Solution
(6.0 x 10^6 kg/s) (9.8 m/s^2) (50m) (.9)
= 2.65 x 10^9 kg*m^2/s^3
I think I did the math right? But am unsure of the units.
Is this the answer? Or should my answer be in watts?
If so how would I get this number to watts?