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Flow Rate Problem (Help!)

  1. Apr 29, 2009 #1
    1. A large tank isopen to the atmosphere and is filled with water. A small hole is 16m below the surface of the water. If the flow rate of the water is out of the hole is 2.5e^3 m^3/min, calculate: a)the velocity of the water as it leaves the hole and b) the diameter of the hole.



    2. Lets say the pool is 1 and the hole is 2, P = pressure and P is density, i was given the equation: P1 + Pv1^2 + 1/2PY1 = P2 + 1/2PV2^2 + PY2


    3. I have no clue how to solve this equation, can someone help me out please?
     
  2. jcsd
  3. Apr 29, 2009 #2

    rl.bhat

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    Check the relevant formula given in 2.
    Inside the pool velocity is zero. And outside the pool Y2 is zero.
     
  4. Apr 29, 2009 #3
    So the equation is:

    P1 + 1/2PY1 = P2 + 1/2PV2^2

    Correct?

    Where do i go from here?
     
  5. Apr 29, 2009 #4

    rl.bhat

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    Again check the left hand side of the equation.
     
  6. Apr 29, 2009 #5
    Can you please explain the equation, i do not understand it so i really do not know what the velocities are
     
  7. Apr 29, 2009 #6

    rl.bhat

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    OK. At the opening what is the total pressure inside the tank?
     
  8. Apr 30, 2009 #7
    Well since it is exposed to the atmosphere, isnt it atmospheric pressure? 1.01x10^5 Pa?
     
  9. Apr 30, 2009 #8

    rl.bhat

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    Plus the pressure due to the water at the depth Y1
     
  10. Apr 30, 2009 #9
    Ok, i've figured it out, thank you for all of your help. I have another problem, should i continue that here or start another thread?
     
  11. Apr 30, 2009 #10

    rl.bhat

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    You can continue here.
     
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