(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

In an ideal fluid, the pipe length is doubled, while radius is decreased by factor 2 what will have to the velocity and volume that is flowing?

2. Relevant equations

Q=Av = pi*r^2*v

3. The attempt at a solution

From this the volume that will pass, in ideal fluid cases, is constant (same throughout), but the velocity will increase by a factor of 4 since: Q/v = pi*r^2. Is this correct?

Also if I were considering the radius decreasing by a factor of 2, in real fluids, the velocity would increase by it would not increase as much as seen in ideal fluids?

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# Homework Help: Flow rate

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